Question

4 tan 45° +(2 sin 45°) (6 cos 45°)​

Answer 1

value of 4 tan 45° +(2 sin 45°) (6 cos 45°)​ is 10.

Explanation:

To solve this question we need to know value of

tan 45° = 1

sin 45° =
`1/√(2)`

cos 45° =
`1/√(2)`

we will be using above value sin the given expression as shown

`4 tan 45 +(2 sin 45) (6 cos 45)​ = 4*1 + (2*1/√(2) )(6*1/√(2))\\ = 4 + (2/√(2)) (6/√(2))\\= 4 + (2*6)/(√(2)*√(2))\\= 4 + (12/2)\\= 4 + 6 = 10`

Thus, value of 4 tan 45° +(2 sin 45°) (6 cos 45°)​ is 10.