Question

Amylose is a "polysaccharide" that plants use to store energy. It is made of repeating subunits of C6H10O5. If a particular amylose molecule has 2537 of these subunits, what is its molecular formula? What is its molar mass? What is the empirical formula of amylose?

Answer 1

Amylose is a polysaccharide made of repeating subunits of C6H10O5. The molecular formula of the amylose molecule is C2537H4051O2536 and its molar mass is 114,165 amu. The empirical formula of amylose is C6H10O5.

Step-by-step explanation:

Amylose is a polysaccharide made of repeating subunits of C6H10O5. If a particular amylose molecule has 2537 of these subunits, its molecular formula would be C2537H4051O2536. To get the molar mass, we can calculate the molecular weight of the subunit which consists of 45 atomic mass unit (amu). So, the molar mass of amylose would be 45 amu multiplied by 2537, which is 114,165 amu. The empirical formula of amylose is C6H10O5 because it represents the simplest whole number ratio of the elements in the molecule.

Answer 2

See exaplanation

Step-by-step explanation:

For this question, we several sub-questions, lets start with the first one:

What is its molecular formula?

For this question we have to multiply the subunit by the number of subunits in the polysaccharide, so:

`(C_6H_1_0O_5)*2537=C_1_5_2_2_2H_2_5_3_7_0O_1_2_6_8_5`

What is its molar mass?

For this question, we have to find the molar mass of 1 subunit and then multiply by the number of subunits:

Atomic masses: C: 12 g/mol H: 1 g/mol O: 16 g/mol

Now we can multiply, the atomic masses by the number of atoms, so:

`(12*6)+(10*1)+(16*5)=~162~g/mol`

If we take into account the number of subunits:

`(162~g/mol)*2537=410994~g/mol`

What is the empirical formula of amylose?

In this case, we have to remember that the empirical formula is the smallest number of atoms. In other words, we have to simplify the formula. Therefore, the smallest formula is the subunit formula:
`C_6H_1_0O_5`.

I hope it helps