Answer: PD = 6
Explanation:
PD = PB + AB = 12
When two secant lines intersect each other outside a circle, the products of their segments are equal. This is:
PB x PA = PD x PC
7 x 12 = PD x 14
PD = 7 x 12 / 14
PD = 6
Answer:
In the given figure, secants PA and PC are intersecting outside of the circle at point P.
PA = PB + AB = 7 + 5 = 12
PC = 14, PD =?
By the property of intersecting secants outside of a circle:
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