Question

Plz help, I don’t mean to hit the first answer

Answer 1

`(1)/(3)\\\\</p><p>(2)/(3)\\\\</p><p>(0)/(12)`

Explanation:

Red blocks = 4, White blocks = 4, Blue blocks = 4, Green blocks = 0

Total blocks = 4 + 4 + 4 = =12

1)

Probability of picking a red block

`=(No. \: of\: red\: blocks)/(Total\: blocks) </p><p>=(4)/(12)</p><p>=(1)/(3)`

2)

Probability of not picking a red block

`=(No. \: of\: white\: and \: blue\: blocks)/(Total\: blocks) \\\\</p><p>=(4+4)/(12)</p><p>=(8)/(12)</p><p>=(2)/(3)`

3)

Probability of picking a green block

`=(No. \: of\: green \: blocks)/(Total\: blocks) </p><p>=(0)/(12)`