Answer:
![(1)/(4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/3ukomx75hu8spviyze2glnxd0n4g4a0skk.png)
Explanation:
The sample space of rolling a six-sided die and a coin is given below:
![\left|\begin{array}c&1&2&3&4&5&6\\--&--&--&--&--&--&--\\H&H1&H2&H3&H4&H5&H6\\T&T1&T2&T3&T4&T5&T6\end{array}\right|](https://img.qammunity.org/2021/formulas/mathematics/college/z26avd8gz03y7pfz9q32e0jmiztqov26r5.png)
Total Number of Possible Outcomes = 12, i.e. n(S)=12
Let the event of getting a head followed by an even number = A
A={H2, H4, H6}
n(A)=3
Therefore:
Probability of getting a head followed by an even number
![=(n(A))/(n(S))\\ =(3)/(12)\\\\=(1)/(4)](https://img.qammunity.org/2021/formulas/mathematics/college/xz9ck3onldcxz6w7xtezfokixxe7mlqetb.png)