Question

12. Linda walks through a road. If her walking speed increases from 1 m/s to 1.5 m/s, she will complete the walk 200 s earlier. Find the distance travelled by Linda.​

Answer 1

600 meters

Explanation:

Case 1 : Speed of 1 m/s

• d = v * t
• d = 1 * t
• d = t [Equation 1]

Case 2 : Speed of 1.5 m/s

• d = v * t
• d = 1.5 * (t - 200)
• d = 1.5t - 300 [Equation 2]

As distance in both cases is the same, equate the values of d from both equations.

• t = 1.5t - 300
• 0.5t = 300
• t = 300 * 2
• t = 600 s

Now, put the value of t in Equation 1 to find d.

• d = 600 meters