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User Nevace
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Answer:

47.5% of students fall within heights of 100 cm to 120 cm

Explanation:

We are given that heights of Grade 1 students are normally distributed

Mean =
\mu = 100 cm

Standard deviation =
\sigma = 10 cm

a)

Empirical rule

68% of data lies within the first standard deviation from the mean i.e
.(\mu-\sigma , \mu+\sigma)=(100-10,100+10)=(90,110)

95% of all the data will fall within two standard deviations i.e.
(\mu-2\sigma , \mu+2\sigma)=(100-2(10),100+2(10))=(80,120)

99.7% of data lies within the three standard deviations i.e.
( \mu - 3 \sigma , \mu +3 \sigma)=(100-3(10),100+3(10))=(70,130)

b)Percentage of students fall within heights of 100 cm to 120 cm

Using the normal distribution curve

Percentage of students fall within heights of 100 cm to 120 cm =
(1)/(2) * 95\% = 47.5\%

Hence 47.5% of students fall within heights of 100 cm to 120 cm

Need help written responses???-example-1
User JamieH
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