Question

2.-Efraín tiene un terreno rectangular cuya área es de 120 m2 + 280 m como se muestra en la Figura:

120 m2 + 280 m

f

De acuerdo con estos datos ¿Cuánto mide el lado f?

a) 12 m2

+ 35

b) 15 m + 35 cm

c) 12 m + 35

d) 15 m + 35

3.- Un niño elaboró cuatro figuras de plastilina: dos prismas cuadrangulares y dos cilindros. ¿En qué figura ocupó

la mayor cantidad de plastilina? JUSTIFICA TU RESPUESTA

a)


b)


c)


e)

8

Answer 1

2) Option D is correct.

f = (15m + 35)

3) Check Explanation

Explanation:

The diagram of the question is presented in the attached image to this question

English Translation

Efraín has a rectangular land whose area is (120m² + 280m) as shown in the figure. According to these data, how much does side f measure?

a) 12 m² + 35

b) 15 m + 35 cm

c) 12 m + 35

d) 15 m + 35

3.- A child made four plasticine figures: two quadrangular prisms and two cylinders. In which figure did you occupy the most amount of modeling clay? JUSTIFY YOUR ANSWER

Solution

2) The area of a rectangle is given as

Area = Length × Breadth

Area = (120m² + 280m)

Length = f

Breadth = 8m

(120m² + 280m) = f × 8m

f = (120m² + 280m)/(8m)

f = (15m + 35)

Option D is correct.

f = (15m + 35)

3) For the second question, the images for the question and the dimensions of the figures aren't provided, hence, a very accurate answer can be provided. But without This, we can only speculate.

The figure that would use the most clay is the figure whose volume is the highest if the volumes of each of the figures are calculated.

Volume of a quadrangular prism = (Area of base) × (perpendicular height)

Volume of a cylinder = (Area of base) × (Height) = (πR² × H) = πR²H

So, it is in the evaluation of these volumes that the solution of this question is obtained.

Hope this Helps!!