185k views
1 vote
what radius (mm) must a steel (iron) ball bearing have if it is to have a mass of 3.25g? density of iron = 7.86g/cm3 V=4/3 pie r3

1 Answer

6 votes

Answer:

Radius of the steel ball is 4.6mm

Step-by-step explanation:

Hello,

To find the radius of the steel, we'll have to calculate it from it's volume which can be gotten from the density of the material.

Data;

Mass = 3.25g

Density = 7.86g/cm³

Density = mass / volume

Volume = mass / density

Volume = 3.25 / 7.86

Volume = 0.413cm³

Volume of a steel = 4/3πr³

0.413 = 4/3 × π × r³

0.413 = 1.33 × 3.14 × r³

0.413 = 4.1762r³

r³ = 0.413 / 4.1762

r³ = 0.099

Take the cube root of both sides

r = 3√(0.099)

r = 0.46cm

From metrics table

1cm = 10mm

0.46cm = x mm

x = (0.46 × 10)

x = 4.6mm

The radius of the steel ball is 4.6mm

User Anjil Dhamala
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.