Question

Ammonia (NH3) is a weak base that reacts with a strong acid to form the ammonium ion, NH4 . In the titration of 15.00 mL of an ammonia cleaner with 0.5000 M HCl, 42.6 mL of the titrant was required to reach the endpoint. What is the concentration of the NH3 in solution

Answer 1

Answer: The concentration of the
`NH_3` in solution is 1.42 M

Step-by-step explanation:

According to neutralization law:

`n_1M_1V_1=n_2M_2V_2`

where,

`n_1` = basicity of
`HCl` = 1

`n_2` = acidity of
`NH_3` = 1

`M_1` = concentration of
`HCl` = 0.5000 M

`M_2` = concentration of
`NH_3` = ?

`V_1` = volume of
`HCl` = 42.6 ml

`V_2` = volume of
`NH_3` = 15.00 ml

Now put all the given values in the above law, we get:

`(1* 0.5000* 42.6)=(1* M_1* 15.00)`

By solving the terms, we get :

`M_1=1.42M`

Thus the concentration of the
`NH_3` in solution is 1.42 M