Answer:
Option (1)
Explanation:
Quadratic equation is given as,
2x² + 8 = 0
Let the function is,
f(x) = 2x² + 8
f(x) = 2(x - 0)² + 8
Now we will prepare the table for every input value,
x -2 -1 0 1 2
y 16 10 8 10 16
By plotting these points we get a parabola having vertex at (0, 8).
Graph of the given function doesn't touches or intersects the x-axis.
And we know if a graph has no x-intercept, function graphed will have no real solution.
Therefore, function f(x) will have no real solutions.
Option (1) will be the answer.