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A hyperbola in the form (x ^ 2)/(a ^ 2) - (y ^ 2)/(b ^ 2) = 1 has a center, vertices, and foci that fall along a horizontal. Please select the best answer from the choices provided. True or false

User Ian
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2 Answers

4 votes

Answer:

It is True!

Explanation:

User AmirModiri
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5.4k points
4 votes

Answer:

True

Explanation:

Explanation:-

The equation of the standard hyperbola is


(x^(2) )/(a^(2) ) - (y^(2) )/(b^(2) ) =1

  • Center is (0,0)
  • Hyperbola is symmetric with respective to both the axes, since if (x, y) is a point on the hyperbola, then (-x, y), (-x,-y), (x,-y) are also lie on the parabola.
  • The relation of between focus and transverse and conjugate axes c²=a²+b²
  • The transverse axis is along x-axis
  • The conjugate axis is along y-axis
  • The length of transverse axis is 2 a
  • The length of conjugate axis is 2 b
  • The foci is (±c,0) and the equation of foci is x=±a e)
  • The length of Latus rectum is
    (2b^(2) )/(a)
A hyperbola in the form (x ^ 2)/(a ^ 2) - (y ^ 2)/(b ^ 2) = 1 has a center, vertices-example-1
User Aliaksei Bulhak
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