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In a game of poker a player receives a subset of 5 cards from a standard deck of 52 cards. There are four suites (clubs, spades, hearts, diamonds) with 13 cards in each suite. What is the probability your hand contains exactly 3 hearts (out of 5 cards)?

User Silvermind
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1 Answer

5 votes

Answer:

8.15% probability your hand contains exactly 3 hearts

Explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the cards are chosen is not important, so we use the combinations formula to solve this question.

Combinations formula:


C_(n,x) is the number of different combinations of x objects from a set of n elements, given by the following formula.


C_(n,x) = (n!)/(x!(n-x)!)

What is the probability your hand contains exactly 3 hearts (out of 5 cards)?

We have 52 cards in total.

13 are clubs, 13 are spades, 13 are hearts, 13 are diamonds.

Desired outcomes:

3 hearts, from a set of 13.

Other 2 cards, from a set of 52-13 = 39.

So


D = C_(13,3)*C_(39,2) = (13!)/(3!(13-3)!)*(39!)/(2!(39-2)!) = 211926

Total outcomes:

5 cards, from a set of 52. So


T = C_(52,5) = (52!)/(5!47!) = 2598960

Probabilities:


p = (D)/(T) = (211926)/(2598960) = 0.0815

8.15% probability your hand contains exactly 3 hearts

User Crimbo
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