How many moles are in 42.9 g of Fe2O4

asked Jun 5, 2021 43.8k views

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5 votes

Answer:

0.24375moles

Step-by-step explanation:

Moles=mass/moler mass

Fe-56

O-16

(56×2)+(16×4)

=176

42.9÷176=0.24375moles

Ksogor answered Jun 10, 2021

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