Answer:
20.0 mph
Step-by-step explanation:
Let x represent the speed in still air, and t represent the time of flight;
Speed of wind = 2 mph
When flying with the wind, it's Speed is;
x + 2
When flying against wind, it's speed is;
x - 2
distance = speed × time;
When flying with the wind, distance is;
(x+2)t = 88 .....1
When flying against wind, distance is;
(x-2)t = 72 .......2
Solving the simultaneous equation;
Divide equation 1 by 2
(x+2)t/(x-2)t = 88/72
(x+2)/(x-2) = 1.222
x+2 = 1.222(x-2)
x+2 = 1.222x - 2.444
x(1.222-1) = 2+2.444
x(0.222) = 4.444
x = 4.444/0.222
x = 20.0 mph
the rate of the bird in still air is 20.0 mph