Question

Suppose you have a 115 kg wooden crate resting on a wood floor, with coefficient of static friction 0.500 between these wood surfaces. (Enter the magnitudes.) (a) What maximum force (in N) can you exert horizontally on the crate without moving it

Answer 1

maximum force (in N) can you exert horizontally on the crate without moving it = 564.075 N

Step-by-step explanation:

Given data:

mass m= 115 kg

coefficient of friction μ =0.5

according to newton law of motion the net force acted on body is given by

`F_(net)=ma=F_(max)- F_(f)`

here the body is in rest ,

`F_(net)=0\\\Rightarrow F_(max)=F_(f)\\\text{frriction force}  F_(f) = \mu* N\\`

N= it is the normal reaction force

N= mg = 115×9.81

therefore,

`F_(f) = 0.5*115*9.81 = 564.075 N = F_(max)`