Question

How many atoms are present in 3.42E23 molecules of Cu Cl?

Answer 1

3.42 × 10²³ atoms CuCl

General Formulas and Concepts:

• Avagadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
• Dimensional Analysis

Step-by-step explanation:

Step 1: Define

3.42E23 molecules CuCl

3.42 × 10²³ molecules CuCl

Step 2: Convert (DA)

`3.42 \cdot 10^(23) \ molecules \ CuCl((6.02 \cdot 10^(23) \ atoms \ CuCl)/(6.02 \cdot 10^(23) \ molecules CuCl) )` = 3.42 × 10²³ atoms CuCl

• molecules CuCl and molecules CuCl cancel out
• left with atoms CuCl as final unit

Step 3: Check

We have 3 sig figs. Follow sig fig rules.

Since our answer already has the correct number of sig figs, there is no need to change it.