Question

Consider the reaction below. 2C6H14 + 19O2 Right arrow. 12CO2 + 14H2O How many moles of hexane (C6H14) must burn to form 18.4 mol of carbon dioxide?

Answer 1

B) 3.07 mol

Step-by-step explanation:

Answer 2

`3.06mol~C_6H_14`

Step-by-step explanation:

We have to start with the reaction:

`2C_6H_1_4 + 19O_2->12CO_2 + 14H_2O`

We have 2 carbons, 6 hydrogens and 38 oxygens on both sides.

Now the molar ratio between
`C_6H_14` and
`CO_2` is 2:12 or
`2~mol~C_6H_14=~12~mol~CO_2`. With this in mind we can calculate the moles of
`C_6H_14`, so:

`18.4~mol~CO_2(2~mol~C_6H_14)/(12~mol~CO_2)=3.06mol~C_6H_14`

I hope it helps!