Answer:
The vertices of the pre-image, rectangle ABCD are (-1, 1), (7, 1), (7, -2) and (-1, -2).
Explanation:
The T-4, 3(x, y) rule of the translation of the pre-image to the image is equal to:
(x, y) = (x - 4, y + 3)
The translation is 4 units to the left and 3 units up .
So the inverse rule of translation of the image to the pre-image is equal to:
(x', y') = (x' + 4, y' - 3)
Consider the provided image below.
The vertices of the rectangle A'B'C'D' are:
A' = (-5, 4)
B' = (3, 4)
C' = (3, 1)
D' = (-5, 1)
Then the vertices of the rectangle ABCD are:
A = (-5+4, 4-3) = (-1, 1)
B = (3+4, 4-3) = (7, 1)
C = (3+4, 1-3) = (7, -2)
D = (-5+4, 1-3) = (-1, -2)
Thus, the vertices of the pre-image, rectangle ABCD are (-1, 1), (7, 1), (7, -2) and (-1, -2).