131,543 views
27 votes
27 votes
What is the solution for the equation -15=5(3y-10)-5y

User Chris Nolet
by
2.7k points

1 Answer

20 votes
20 votes

Answer:


  • \Large\boxed{\sf{y=(7)/(2) }}

Explanation:

Isolate the variable of y from one side of the equation.

-14=5(3y-10)-5y

First, switch sides.


\sf{5\left(3y-10\right)-5y=-15}

Use the distributive property.

DISTRIBUTIVE PROPERTY:

A(B-C)=AB-AC

5(3y-10)

Multiply by expand.

5*3y=15y

5*10=50

15y-50-5y

15y-5=10y

= 10y-50

10y-50=-15

Add by 50 from both sides.

10y-50+50=-15+50

Solve.

10y=35

Then, you divide by 10 from both sides.

10y/10=35/10

Solve.

Divide the numbers from left to right.

35/10=7/2

y=7/2

Divide is another option.

7/2=3.5


\Longrightarrow: \boxed{\sf{y=(7)/(2)}}

  • Therefore, the correct answer is y=7/2.

I hope this helps. Let me know if you have any questions.

User Niran
by
3.3k points