Answer:
Hence, the system of equation does not have solution.
Explanation:
You have the following 2x2 system:
![x-2y=1\ \ \ \ (1)\\\\-4x+8y=-4\ \ \ \ (2)](https://img.qammunity.org/2021/formulas/mathematics/college/m5g8tobc4tm24v4d12fj3yxhf1vtuf7q1s.png)
You can obtain the solution to the system by using substitution method.
You solve the first equation for x:
(3)
Next, you replace (3) in the equation (2), and you solve for y:
![-4(1+2y)+8y=-4\\\\-4-8y+8y=-4\\\\0=0](https://img.qammunity.org/2021/formulas/mathematics/college/oa4ufvp16m9y7opsqsbdagnaqrcxo7v43q.png)
The last result is the trivial solution. This means that the equation (2) is a multiple scale of the first equation. In fact, if you multiply equation (1) by -4, you obtain the equation (2).
Hence, the system of equations does not have solution.