Question

The following data represent the pulse rates? (beats per? minute) of nine students enrolled in a statistics course. Treat the nine students as a population.Complete parts ?(a) through? (c). Student Pulse ??Perpectual Bempah 64 ??Megan Brooks 77 ??Jeff Honeycutt 89 ??Clarice Jefferson 69 ??Crystal Kurtenbach 89 ??Janette Lantka 65 ??Kevin McCarthy 88 ??Tammy Ohm 69 ??Kathy Wojdya 87(a) Determine the population mean pulse. The population mean pulse is approximately nothing beats per minute. ?(Round to one decimal place as? needed.)(b) Determine the sample mean pulse of the following two simple random samples of size 3. Sample? 1: StartSet Janette comma Clarice comma Megan EndSet Sample? 2: StartSet Perpectual comma Clarice comma Megan EndSet The mean pulse of sample 1 is approximately nothing beats per minute. ?(Round to one decimal place as? needed.) The mean pulse of sample? 2, is approximately nothing beats per minute. ?(Round to one decimal place as? needed.)(c) Determine if the means of samples 1 and 2? overestimate, underestimate, or are equal to the population mean. The mean pulse rate of sample 1 ? (underestimates/ is equal to/ overestimates) the population mean. The mean pulse rate of sample 2 (is equal to/ underestimates/ or overestimates) the population mean.

Answer 1

The question involves calculating the mean pulse rate of a population and that of two samples and then comparing the samples' means to the population mean.

Step-by-step explanation:

The question requires calculating the population mean pulse rate, and the mean pulse rates of two samples, followed by a comparison between the sample means and the population mean. To find the population mean, we add up all the pulse rates and then divide by the number of students. To find the sample means, we simply add the pulse rates for the students in each sample and then divide by the number of students in the sample. In part (c), we compare each sample mean to the population mean to determine whether they overestimate, underestimate, or are equal to the population mean.

Answer 2

(a)77.4bpm

(b)Mean of Sample 1 = 70.3 beats per minute.

Mean pulse of sample 2 = 70 beats per minute.

(c)

• The mean pulse rate of sample 1 underestimates the population mean.
• The mean pulse rate of sample 2 underestimates the population mean.

Step-by-step explanation:

(a)Population mean pulse.

The pulse of the nine students which represent the population are:

• Perpectual Bempah 64
• Megan Brooks 77
• Jeff Honeycutt 89
• Clarice Jefferson 69
• Crystal Kurtenbach 89
• Janette Lantka 65
• Kevin McCarthy 88
• Tammy Ohm 69
• Kathy Wojdya 87

`\text{Population Mean} =(64+77+89+69+89+65+88+69+87)/(9) \\=(697)/(9) \\\\=77.44`

The population mean pulse is approximately 77.4 beats per minute.

(b)Sample 1: {Janette,Clarice,Megan}

• Janette: 65bpm
• Clarice: 69bpm
• Megan: 77bpm

Mean of Sample 1

`\text{Sample 1 Mean} =(65+69+77)/(3) \\=(211)/(3) \\\\=70.3`

Sample 2: {Janette,Clarice,Megan}

• Perpetual: 64bpm
• Clarice: 69bpm
• Megan: 77bpm

Mean of Sample 2

`\text{Sample 2 Mean} =(64+69+77)/(3) \\=(210)/(3) \\\\=70`

The mean pulse of sample 1 is approximately 70.3 beats per minute.

The mean pulse of sample 2 is approximately 70 beats per minute.

(c)

• The mean pulse rate of sample 1 underestimates the population mean.
• The mean pulse rate of sample 2 underestimates the population mean.