182k views
2 votes
Divide these polynomials (8x^3+2x^2-7x+2)/(2x-1)

User Modder
by
7.0k points

1 Answer

3 votes

Answer:


4x^2+3x-2

Explanation:

We are given that


(8x^3+2x^2-7x+2)/(2x-1)

We have to divide the polynomials.

We have

Divisor polynomial=
2x-1

Dividend polynomial=
8x^3+2x^2-7x+2


(8x^3+2x^2-7x+2)/(2x-1)=4x^2+3x-2

Quotient=
4x^2+3x-2

Remainder=0

Divide these polynomials (8x^3+2x^2-7x+2)/(2x-1)-example-1
User Mardo
by
6.4k points