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Urgent, Please help!

Urgent, Please help!-example-1

1 Answer

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Answer:

min: 52

max: 78

median: 63

lower quartile median: 54

upper quartile median: 73

interquartile range: 19

Explanation:

the temperatures ordered from least to greatest

52, 53, 54, 54, 57, 62, 64, 69, 73, 73, 77, 78

the min is 52

the max is 78

median:

52, 53, 54, 54, 57, 62, 64, 69, 73, 73, 77, 78

(62+64)/2=126/2=63

thus the median is 63

now we don't include the median in finding the upper and lower quartile medians:

lower quartile median:

52, 53, 54, 54, 57, 62

54 (same #s no need to add up and divide by 2)

upper quartile median:

64, 69, 73, 73, 77, 78

73 (same #s no need to add up and divide by 2)

interquartile range is:

upper quartile median-lower quartile median:

73-54

19

User Pmjobin
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