Answer:
81.45% probability all four systems would operate properly for at least 3 years
Explanation:
For each traffic light, there are only two possible outcomes. Either they work for at least 3 years, or they do not. The probability of a light working at least 3 years is independent of other lights. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
![P(X = x) = C_(n,x).p^(x).(1-p)^(n-x)](https://img.qammunity.org/2021/formulas/mathematics/college/mj488d1yx012m85w10rpw59rwq0s5qv1dq.png)
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
![C_(n,x) = (n!)/(x!(n-x)!)](https://img.qammunity.org/2021/formulas/mathematics/college/qaowm9lzn4vyb0kbgc2ooqh7fbldb6dkwq.png)
And p is the probability of X happening.
95% of the newly developed systems lasted 3 years
This means that
![p = 0.95](https://img.qammunity.org/2021/formulas/mathematics/college/xxm1a38z56izt8nlvei8i4idmdchgpasbt.png)
The city purchases four systems
This means that
![n = 4](https://img.qammunity.org/2021/formulas/mathematics/college/y06ebs697ivju46r29350k0r0rbmcgv2zl.png)
What is the probability all four systems would operate properly for at least 3 years
This is P(X = 4).
![P(X = x) = C_(n,x).p^(x).(1-p)^(n-x)](https://img.qammunity.org/2021/formulas/mathematics/college/mj488d1yx012m85w10rpw59rwq0s5qv1dq.png)
![P(X = 4) = C_(4,4).(0.95)^(4).(0.05)^(0) = 0.8145](https://img.qammunity.org/2021/formulas/mathematics/college/1dun0adixchkwa735p8l360nbgty70zjpu.png)
81.45% probability all four systems would operate properly for at least 3 years