Answer:
In this problem, we have three vertices, namely:
A(-2,2) , B(-2,4) , C(0,0)
Our transformation rule is (x+3,y-2) and this rule forms the image A'B'C'. So:
Explanation:
A'=(-2+3,2-2)=(1,0)
B'=(-2+3,4-2)=(1,2)
C'=(0+3,0-2)=(3,-2)
Taking a look in the First Figure, we can see the two triangles. The red one is the triangle ABC and the blue one is A'B'C'. In the Second Figure, the corresponding vertices have been connected with line segments, as indicated the green lines. The characteristics of those three lines are two, namely:
They are parallel.
They have the same length.