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An object is launched directly in the air at a speed of 64 feet per second from a platform located 16 feet in the air. The motion of the object can be modeled using the function f(t)=−16t2+64t+16, where t is the time in seconds and f(t) is the height of the object. When, in seconds, will the object reach its maximum height?

User Jacobm
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1 Answer

3 votes

Answer:

Explanation:

x= -b/2a = -64/2(-16) = 2

showing that the object will reach its highest point at 2 seconds

User Stefs
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