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Write the equation of a line that passes through the point (–10, 2) that has a slope of .5

User LLF
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1 Answer

7 votes

Answer:

y=(.5)x+7

Explanation:

Hello. For this question, they are asking us to find the equation of a line. A line has this form: y=mx+b.

For this question they will want us to give the answer with x and y as variables (letters) and m and b (the slope and y-intercept respectivly) with numerical values.

First, we can put in the point into the equation. The point given is (-10,2) so the x value is -10 and they y value is 2.

y=mx+b

2=m(-10)+b

Then we know that the slope is .5, so we can put that in as m.

2=(.5)(-10)+b

Solving for b, we get that it is equal to 7.

[2+5=b] b=7

Therefore, the equation for the line would be:

y=(.5)x+7

User Rajeev Sharma
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