Question

A table has an area of 12 and a perimeter of 16 ft. What are the dimensions of the table?

Answer 1

l=6

w=2

Area=lw

Area=6×2

area=12

perimeter=2(l+w)

perimeter=2(6+2)

perimeter=2×8

perimeter=16

Mark brianliest if my answer suit your question.

Answer 2

2 feet by 6 feet

Explanation:

L x b is 12

l x 12/b

perimiter is 16

2 (l plus b) is 16

l plus b is 8

12/b plus b is 8

B² - 8b plus 12 is 0

B2 - 6B- 2b plus 12 is 0

(b- 2) (b-6) is 0

B-2 is 0 and b-6 is 0

B Is 2,6

L = 12/2 is 6

L = 12/6 is 2

so is 2,6