*see attachment for the megaphone being referred to here
Answer:
9%
Explanation:
==>Given:
Conical megaphone with the following dimensions:
Slant height (s) = 2.25 ft
Diameter (D) = 1.2 ft (radius r = 0.6 ft)
π = 3.1
Area covered by sticker on one side = area of square = 6 in × 6 in = 0.5 ft × 0.5 ft = 0.25 ft²
==>Required
% of the surface of area of the conical megaphone that is covered by the sticker = area covered by the sticker ÷ surface area of megaphone × 100
==>SOLUTION
Area covered by sticker on both sides = 0.25 ft² + 0.25 ft² = 0.5 ft²
Surface area of the megaphone = surface area of a cone = πrs + πr²
S.A of megaphone = (3.14 × 0.6 × 2.25) + (3.14 × 0.6²)
S.A = 4.239 + 1.1304
S.A = 5.3694 ft²
Therefore, % of the surface of area of the conical megaphone that is covered by the sticker = 0.5 ÷ 5.3694 × 100
= 9.31202741
= 9%