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What is the value of A when r=9 in inverse proportions

What is the value of A when r=9 in inverse proportions-example-1

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Answer:

3.6 and 2

Explanation:

Given R is inversely proportional to A then the equation relating them is

R =
(k)/(A) ← k is the constant of proportion

To find k use the condition R = 12 when A = 1.5, that is

12 =
(k)/(1.5) ( multiply both sides by 1.5 )

18 = k

R =
(18)/(A) ← equation of proportion

(a)

when A = 5, then

R =
(18)/(5) = 3.6

(b)

when R = 9, then

9 =
(18)/(A) ( multiply both sides by A )

9A = 18 ( divide both sides by 9 )

A = 2

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