Answer:
iron (Fe)
Step-by-step explanation:
Use q = mcΔT.
q = 1.396 x 10^2 J
m = 15.5g
ΔT = (45.0 - 25.0) = 20 degrees celcius
1.396 x 10^2 = 15.5 x c x 20
c = .450 J/g x degrees celcius
This is closest to the specific heat of iron/steel.
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