Answer:
The length of segment DC is 33 units.
Explanation:
A perpendicular bisector of line segment divides the line into two equal parts at 90°.
This implies that the perpendicular bisector of line segment AC at B divides the line Ac into two equal parts AB and BC.
It is given that:
BC = 23 units
AB = 2x + 7 units
AD = 4x + 1 units
The measure of AB is 23 units, according to the perpendicular bisector definition.
Compute the value of x as follows:
AB = 2x + 7
23 = 2x + 7
2x = 23 - 7
2x = 16
x = 8 units
Then the measure of side AD is:
AD = 4x + 1
= 4 × 8 + 1
= 32 + 1
= 33 units
Consider the diagram below.
Consider the right-angled triangle ABD.
Use Pythagoras theorem to compute the length of DB² as follows:
![AD^(2)=DB^(2)+AB^(2)\\\\33^(2)=DB^(2)+23^(2)\\\\DB^(2)=560](https://img.qammunity.org/2021/formulas/mathematics/high-school/it9vnyjlo5r6rjjgoaxzzkgsy7qiaan2w3.png)
Consider the right angles triangle DBC.
Use Pythagoras theorem to compute the length of DC² as follows:
![DC^(2)=DB^(2)+BC^(2)\\\\=560+23^(2)\\\\=560+529\\\\=1089\\\\DC=√(1089)\\\\=33](https://img.qammunity.org/2021/formulas/mathematics/high-school/ip2iljnr9kf5pppsi1tdn4digapelo2k0y.png)
Thus, the length of segment DC is 33 units.