Question

Ayla hangs a 7.3 kg bowling ball from the ceiling by a rope of negligible mass. The rope will break if the tension in the rope exceeds 110 N. What minimum force must Ayla's dog Rufus exert on the bowling ball to break the rope. A. 72 N B. 103 N C. 48 N D. 38 N

Answer 1

D. 38 N

Step-by-step explanation:

Given;

mass of bowling ball, m = 7.3 kg

maximum tension on the rope before it breaks,
`T_(max)` = 110 N

weight of Ayla's dog Rufus + weight of the bowling ball = maximum tension on the rope

weight of Ayla's dog Rufus, is the minimum force that will be added to the bowling ball to break the rope.

weight of the bowling ball = mg = (7.3 kg) x (9.8 m/s²) = 71.54 N

weight of Ayla's dog Rufus + 71.54 N = 110 N

weight of Ayla's dog Rufus = 110 N - 71.54 N

weight of Ayla's dog Rufus = 38.46 N

weight of Ayla's dog Rufus ≅ 38 N

Thus, weight of Ayla's dog Rufus is the minimum force that will be added to the bowling ball to break the rope = 38 N

The correction is "D. 38 N"