Answer:
Explanation:
Corresponding weight gains between siblings that received supplement and month and siblings that did not receive supplement.
The data for the test are the differences between the weight gains of siblings that received supplement and siblings that did not receive supplement.
μd = weight gains of siblings that received supplement minus the weight gains of siblings that did not receive supplement.
received not received diff
70.4 69.3 1.1
38.2 37.2 1
59.7 58.7 1
40.3 39.3 1
93.5 92.5 1
50.7 49.6 1.1
Sample mean, xd
= (1.1 + 1 + 1 + 1 + 1 + 1.1)/6 = 1.03
xd = 1.03
Standard deviation = √(summation(x - mean)²/n
n = 6
Summation(x - mean)² = (1.1 - 1.03)^2 + (1 - 1.03)^2 + (1 - 1.03)^2+ (1 - 1.03)^2 + (1 - 1.03)^2 + (1.1 - 1.03)^2 = 0.0134
Standard deviation = √(0.0134/6
sd = 0.047
For the null hypothesis
H0: μd ≥ 0
For the alternative hypothesis
H1: μd < 0
The distribution is a students t. Therefore, degree of freedom, df = n - 1 = 6 - 1 = 5
The formula for determining the test statistic is
t = (xd - μd)/(sd/√n)
t = (1.03 - 0)/(0.047/√6)
t = 53.68
We would determine the probability value by using the t test calculator.
p < 0.00001
Assume alpha = 0.05
Since alpha, 0.05 > than the p value, then we would reject the null hypothesis. Therefore, there is no significant evidence that the supplement increases weight gain