Question

What is the volume occupied by 3.00 mol of hydrogen gas at STP? *

Answer 1

Answer: V=67.2 L

Step-by-step explanation:

For this problem we will need to use the Ideal Gas Law.

Ideal Gas Law: PV=nRT

P=1.00 atm (STP)

V=?

n=3.00 mol

R=0.08206Latm/Kmol

T=273.15 K (STP)

To find V, we would manipulate the equation to V=nRT/P

`V=((3.00 mol)(0.08206Latm/Kmol)(273.15K))/(1.00 atm)`

`V=67.244 L`

With significan figures, our answer is V=67.2 L.