Question

What is the equation of the line that passes through the point (9, 6) and is perpendicular to the line y = 3x - 5?

Answer 1

Explanation:

y = 3x - 5

m₁ = 3

The required line is perpendicular to y = 3x - 5. Let the required line's slope be m₂

m₂ = -1/m₁

m₂ = -1/3

Point (9,6)

Equation of line: y - y₁ = m(x - x₁)

y - 6 = (-1/3)(x - 9)

`y-6=(-1)/(3))x+(1)/(3)*9\\\\y-6=(-1)/(3)x+3\\\\y=(-1)/(3)x+3+6\\\\y=(-1)/(3)x+9\\`