Question

How many atoms are there in 65.8g H2O?

Answer 1

2,198,081,377,400,000,000,000,000 atoms

Step-by-step explanation:

Avogadro's number = 6.02214076 ×
`10^(23)`

One mole of any element, including atoms, is Avogadro's number of them.

H2O = 18g/mol

Mass → Moles and Moles → Atoms

65.8g/18g/mol = 3.65 moles of H2O

3.65 moles x 6.02214076 ×
`10^(23)` = 2,198,081,377,400,000,000,000,000 atoms