Answer:
The height is 87.5 in
Explanation:
We can solve the height of a square pyramid using the Pythagoras theorem, this is because the slant height the height and the section of the base form a right triangle
the slant height is equivalent to the hypotenuse
the height is equivalent to the opposite
while the base(half) is the adjacent
Given
the base of the pyramid=
![22.2 in](https://img.qammunity.org/2021/formulas/mathematics/high-school/98goiakq3s4dzrx5y4pwrmxjnjvic6srax.png)
the adjacent is =
![(22.2)/(2) = 11.1 in](https://img.qammunity.org/2021/formulas/mathematics/high-school/e5fug7izimuivmwk8g3wh1s823o2c88k0h.png)
the slant height (hypotenuse)=
![88.2 in](https://img.qammunity.org/2021/formulas/mathematics/high-school/dx5x0423cvwkyld3oloby1vlghx54z9crq.png)
we know that Pythagoras theorem states that "The sum of the squares of the lengths of the legs of a right triangle ('a' and 'b' in the triangle) is equal to the square of the length of the hypotenuse ('c').
![c^2=a^2 + b^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/owuzshd2oncxkohm6rkd06w1h0x80nifp0.png)
![hyp^2=opp^2+adj^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/353p1iua8druzswxcceteps0fezz738h4m.png)
substituting we have
![88.2^2=opp^2+11.1^2\\opp^2= 88.2^2-11.1^2\\opp^2=7779.24-123.21\\opp^2=7656.03\\opp=√(7656.03) \\opp=87.498\\opp=87.50 in](https://img.qammunity.org/2021/formulas/mathematics/high-school/bmc0xqewqm0veodlmqavpe7tqcvinad004.png)