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What is the product x^2-16 over 2x+8 • x^3-2x^2+x over x^2+3x-4

1 Answer

3 votes

Answer:


(x^3-5x^2 +4x)/(2x+8)

Explanation:

The basic idea is to factor each expression and cancel common factors from numerator and denominator.


(x^2-16)/(2x+8)\cdot(x^3-2x^2 +x)/(x^2+3x-4)=((x-4)(x+4))/(2(x+4))\cdot(x(x-1)^2)/((x+4)(x-1))\\\\=((x-4)x(x-1))/(2(x+4))\cdot((x+4)(x-1))/((x+4)(x-1))\\\\=\boxed{(x^3-5x^2 +4x)/(2x+8)}

User Yaron Levi
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