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Solve the exponential equation using logarithmic properties y=3^2x-4

The 2x is an exponent

User Degs
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1 Answer

3 votes

Answer:


(log(y+4))/(2log3)

Explanation:

Given the exponential equation
y = 3^(2x)+4, to get 2x, we will make 2x the subject of the formula as shown;


y = 3^(2x)-4\\y+4 = 3^(2x)\\taking\ log\ of\ both\ sides\\log(y+4) = log3^(2x)\\ log(y+4) = 2xlog3\\dividing\ both\ sides\ by\ 2log 3\\\ x = (log(y-4))/(2log3) \\

The last expression gives the required value of x

User Roshida
by
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