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3 votes
What is the minimum point of the equation y=2^+8x+9

User Eelvex
by
8.2k points

2 Answers

2 votes

Answer:

y=8x+9

Explanation:

User Nati Sholman Oskar
by
7.8k points
2 votes

Answer:

(-2, 1)

Explanation:

y=2x^2+8x+9

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min is achieved at x= -b/2a

  • x= -8/2*2= -2, then
  • y= 2*(-2)^2+8*(-2)+9= 8-16+9= 1

So min point is (-2, 1)

User Johnny Willer
by
8.1k points

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