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An object is dropped from a bridge and allowed to freefall to the ground. The height of the object over time can be modeled using h(t) = 144 – 16t2.

How many seconds will it take the object to reach the ground?

User Poonam
by
6.8k points

1 Answer

4 votes

Answer: *For 2 being an exponent*: 3 seconds

*For 2 being multiplied to t* : 4.5 seconds

Explanation:

*For 2 being an exponent*

It says we want to know the time it will take to reach the ground. This means that the height will be 0 at this time.

So we can set h(t) = 0 and solve for t.


0 = 144 - 16t^2

Subtract 144:
-144 = -16t^2

Divide -16:
9 = t^2

Now square root:
3 = t

So it will take 3 seconds to reach the ground.

*For 2 being multiplied to t*

It says we want to know the time it will take to reach the ground. This means that the height will be 0 at this time.

So we can set h(t) = 0 and solve for t.


0 = 144 - 16t2

We can simplify by multiplying the -16 and 2:
0 = 144 - 32t

Subtract 144:
-144 = -32t\\

Divide by -32: 4.5 = t

So it will take 4.5 seconds to reach the ground.

User Eddiezane
by
7.5k points
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