Question

Triangle JKL is transformed using the rule . Point K of the pre-image is at (4, 7). What are the coordinates of point K" on the final image? (–7, –4) (–4, –7) (4, –7) (4, 7)

Answer 1

Answer: C

(4, –7)

Explanation:

(–7, –4)

(–4, –7)

(4, –7)

(4, 7)

Answer 2

Option C.

Explanation:

Consider the complete question is "Triangle JKL is transformed using the rule
`R(O,90^\circ)\circ r_(y=-x)(x,y)`. Point K of the pre-image is at (4, 7). What are the coordinates of point K'' on the final image?".

According to
`r_(y=-x)(x,y)`, we get

`(x,y)\rightarrow (-y,-x)`

According to
`R(O,90^\circ)`, we get

`(x,y)\rightarrow (-y,x)`

The rule
`R(O,90^\circ)\circ r_(y=-x)(x,y)` means first reflection and then rotation.

We need to find the image of K(4,7).

After reflection, we get

`K(4,7)\rightarrow K'(-7,-4)`

After rotation, we get

`K'(-7,-4)\rightarrow K''(4,-7)`

Therefore, the correct option is C.