In ΔJKL, the measure of ∠L=90°, the measure of ∠K=77°, and LJ = 6.9 feet. Find the length of JK to the nearest tenth of a foot.

Question

asked Aug 24, 2021 37.4k views

1 Answer

Jqwha · Answer 1 · 2021-08-29T03:53:59+0000

Answer:

JK = 7.1 ft

Explanation:

For angle K, JL is the opposite leg. JK is the hypotenuse. The trig ratio that relkates the opposite leg to the hypotenuse is the sine.

$\sin A = (opp)/(hyp)$

$\sin K = (JL)/(JK)$

$\sin 77^\circ = (6.9)/(JK)$

$(JK)\sin 77^\circ = 6.9$

$JK = (6.9)/(\sin 77^\circ)$

JK = 7.1