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In ΔJKL, the measure of ∠L=90°, the measure of ∠K=77°, and LJ = 6.9 feet. Find the length of JK to the nearest tenth of a foot.

User Changhwan
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1 Answer

4 votes

Answer:

JK = 7.1 ft

Explanation:

For angle K, JL is the opposite leg. JK is the hypotenuse. The trig ratio that relkates the opposite leg to the hypotenuse is the sine.


\sin A = (opp)/(hyp)


\sin K = (JL)/(JK)


\sin 77^\circ = (6.9)/(JK)


(JK)\sin 77^\circ = 6.9


JK = (6.9)/(\sin 77^\circ)


JK = 7.1

User Jqwha
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