Question

David starts at rest and increase it's speed to 10 m/s in 10s. what is it's acceleration?​

Answer 1

Hey!!

Solution,

Initial velocity(u)=0 m/s

Final velocity(v)=10m/s

Time(t)=10s

Acceleration=?

Now,

Acceleration=v-u/t

=10-0/10

= 10/10

=1 m/s^2

The acceleration is 1 m/s^2

Hope it helps

Good luck on your assignment

Answer 2

a=1 m/s^2

Step-by-step explanation:

`a = (v - u)/(t) \\ = (10 - 0)/(10) \\ = 1m {s}^( - 2)`