Answer:
So as the reaction proceeds we lose energy as the reaction is exothermic due to the delta H being negative, this shows that heat flows from the system to its surroundings.
Step-by-step explanation:
2H6O (l) + 3O2 (g) = 2CO2 (g) + 3H2O (g)
2CH3CH2OH(l) + 3O2(g) = 2CO2(g) + 3H2O(g) ΔH = -1234.8kJ/mol
I'm pretty sure this is what your equation is supposed to be, seems to be an error where you've pasted it and it's replaced the O's with )
So as the reaction proceeds we lose energy as the reaction is exothermic due to the delta H being negative, this shows that heat flows from the system to its surroundings.