Register

Consider the reaction between barium chloride and sodium sulphate. If 25.0 mL of 0.75 M barium chloride react, how many grams of solid are produced?

Consider the reaction between barium chloride and sodium sulphate. If 25.0 mL of 0.75 M barium chloride react, how many grams of solid are produced?
96.8k views
1 vote
Consider the reaction between barium chloride and sodium sulphate. If 25.0 mL of 0.75 M barium chloride react, how many grams of solid are produced?

User Hockeybro
by
8.2k points

1 Answer

3 votes
C=n/v => n=CxV (convert V=25ml=0.025L)
n=0.75x0.025= 0.01875
m=n/M
m= 0.01875/(108+35.5x2) = 3.35625g

I’m pretty sure that’s the way to solve it but the answer is pretty small that kinda make me uncomfortable
User Scherf
by
8.3k points
← Prev Question Next Question →

Related questions

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

Compare and contrast an electric generator and a battery??
How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
Can someone complete the chemical reactions, or write which one do not occur, and provide tehir types? *c2h4+h2o *c3h8 + hcl *c2h2+br2 *c4h10+br2 *c3h6+br2
Link Copied!