Question

The conversion of methyl isonitrile to acetonitrile in the gas phase at 250 °C CH3CN(g) is first order in CH3NC with a rate constant of 3.00×10^-3 s-1. If the initial concentration of CH3NC is 5.45×10^-2 M, the concentration of CH3NC will be 1.56×10^-2 M after_____________ s have passed.

Answer 1

Answer: The concentration of
`CH_3NC` will be
`1.56* 10^(-2)M` after 416 seconds have passed.

Step-by-step explanation:

Expression for rate law for first order kinetics is given by:

`t=(2.303)/(k)\log(a)/(a-x)`

where,

k = rate constant =
`3.00* 10^(-3)s^(-1)`

t = age of sample = ?

a = let initial amount of the reactant =
`5.45* 10^(-2)M`

a - x = amount left after decay process =
`1.56* 10^(-2)M`

`t=(2.303)/(3.00* 10^(-3))\log(5.45* 10^(-2))/(1.56* 10^(-2))`

`t=416s`

The concentration of
`CH_3NC` will be
`1.56* 10^(-2)M` after 416 seconds have passed.