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Two perpendicular lines intersect on the -axis. The equation of one line is y- 4x-6=0. Determine the equation of the other line.

User Thebadguy
by
8.0k points

1 Answer

5 votes

Answer:

y =
-(1)/(4)x + 6 or y =
-(1)/(4)x - 0.375

Explanation:

For 2 lines to be perpendicular, their slopes must be negative reciprocals. In order to find the perpendicular of y - 4x - 6 = 0:

SLOPE INTERCEPT FORM: y = 4x + 6

SLOPE OF LINE A: m=4

SLOPE OF LINE B (the one you are looking for): m=
-(1)/(4)

Since I don't know if you meant that they intercept on the x or y axis I will do both.

y-axis

y-6=
-(1)/(4)(x-0)

y =
-(1)/(4)x+6

x-axis

y-0=
-(1)/(4)(x-1.5)

y=
-(1)/(4)x-0.375

User GuidoS
by
7.8k points

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